Ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i d\u00e0n \u0111\u1eb7c bi\u1ec7t \u2013 d\u00e0n \u0111\u1ec1 c\u00f3 l\u00e3i<\/h1>\n<\/div>\n\n\n\n\n\n\n\n<\/div>\n<\/div>\n<\/div>\n<\/p>\n<\/div>\n
<\/p>\n
B\u00e0i vi\u1ebft h\u00f4m nay xin g\u1eedi \u0111\u1ebfn c\u00e1c b\u1ea1n m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh d\u00e0n \u0111\u1eb7c bi\u1ec7t<\/strong><\/span> \u2013 d\u00e0n \u0111\u1ec1 x\u1ed5 s\u1ed1 3 mi\u1ec1n \u0111\u1ec3 c\u00f3 l\u00e3i v\u00e0 gi\u1ea3m thi\u1ec3u x\u00e1c su\u1ea5t tr\u01b0\u1ee3t nh\u1ea5t.<\/p>\n\nM\u1ee5c L\u1ee5c<\/p>\n
\n- 1.Ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i d\u00e0n \u0111\u1eb7c bi\u1ec7t<\/li>\n
- 2. D\u00e0n \u0111\u1eb7c bi\u1ec7t ch\u01a1i trong ng\u00e0y\n
\n- 2.1. D\u00e0n \u0111\u1eb7c bi\u1ec7t 19 s\u1ed1<\/li>\n
- 2.2. D\u00e0n \u0111\u1eb7c bi\u1ec7t 36 s\u1ed1<\/li>\n
- 2.3. D\u00e0n \u0111\u1eb7c bi\u1ec7t 51 s\u1ed1<\/li>\n
- 2.4. D\u00e0n \u0111\u1eb7c bi\u1ec7t 64 s\u1ed1<\/li>\n<\/ul>\n<\/li>\n
- 3. D\u00e0n \u0111\u1eb7c bi\u1ec7t nu\u00f4i 2 ng\u00e0y<\/li>\n
- 4. D\u00e0n \u0111\u1eb7c bi\u1ec7t nu\u00f4i 3 ng\u00e0y<\/li>\n<\/ul>\n<\/div>\n
1.Ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i d\u00e0n \u0111\u1eb7c bi\u1ec7t<\/span><\/h2>\nD\u00e0n \u0111\u1eb7c bi\u1ec7t ngh\u0129a l\u00e0 ch\u01a1i nhi\u1ec1u s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t t\u1ea1o th\u00e0nh d\u00e0n nh\u01b0 : d\u00e0n \u0111\u1eb7c bi\u1ec7t 19 s\u1ed1, 36 s\u1ed1, 51 s\u1ed1, 64 s\u1ed1.<\/p>\n
\u0110\u1ec3 ch\u01a1i \u0111\u01b0\u1ee3c theo c\u00e1c ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u00f3 l\u00e3i th\u00ec y\u1ebfu t\u1ed1 t\u1ec9 l\u1ec7 \u0103n r\u1ea5t quan tr\u1ecdng.B\u00ecnh th\u01b0\u1eddng ch\u00fang ta ghi b\u00ean ngo\u00e0i s\u1ebd \u0103n t\u1ec9 l\u1ec7 1 \u0103n 70, n\u01a1i n\u00e0o cao th\u00ec 1 \u0103n 80 ho\u1eb7c h\u01a1n 80 t\u00ed.<\/p>\n
Ngh\u0129a l\u00e0 ch\u00fang ta gi 1 ngh\u00ecn \u0111\u1ec1 n\u1ebfu tr\u00fang \u0111\u01b0\u1ee3c 99 ngh\u00ecn, 1 \u0111i\u1ec3m l\u00f4 = 27 ngh\u00ecn n\u1ebfu tr\u00fang \u0111\u01b0\u1ee3c 99 ngh\u00ecn.<\/p>\n
Sau \u0111\u00e2y, s\u1ebd chia s\u1ebb m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i d\u00e0n \u0111\u1ec1 \u0111\u1ec3 kh\u1ea3 n\u0103ng c\u00f3 l\u00e3i cao h\u01a1n.<\/p>\n
2. D\u00e0n \u0111\u1eb7c bi\u1ec7t ch\u01a1i trong ng\u00e0y<\/span><\/h2>\nV\u1edbi ph\u01b0\u01a1ng ph\u00e1p d\u00e0n \u0111\u1eb7c bi\u1ec7t ch\u01a1i trong ng\u00e0y n\u00e0y ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i c\u00e1c d\u00e0n 36 s\u1ed1, 51 s\u1ed1 ho\u1eb7c 64 s\u1ed1.<\/p>\n
2.1. D\u00e0n \u0111\u1eb7c bi\u1ec7t 19 s\u1ed1<\/span><\/h3>\nD\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 1 ch\u1ea1m ( 1 \u0111\u1ea7u v\u00e0 1 \u0111u\u00f4i ), 1 \u0111\u1ea7u 1 \u0111u\u00f4i l\u00e0 20 s\u1ed1 nh\u01b0ng c\u00f3 1 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 19 con.V\u00ed d\u1ee5 ch\u1ea1m 1 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1 v\u00e0 \u0111u\u00f4i 1 d\u00e0n n\u00e0y c\u00f3 1 s\u1ed1 tr\u00f9ng l\u00e0 11.<\/p>\n
T\u1ec9 l\u1ec7 ch\u01a1i : ch\u01a1i \u0111\u1ec1u ti\u1ec1n m\u1ed7i ng\u00e0y<\/p>\n
L\u00e3i n\u1ebfu tr\u00fang : 63 ngh\u00ecn<\/p>\n
2.2. D\u00e0n \u0111\u1eb7c bi\u1ec7t 36 s\u1ed1<\/span><\/h3>\nD\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 2 ch\u1ea1m ( 2 \u0111\u1ea7u v\u00e0 2 \u0111u\u00f4i ), 2 \u0111\u1ea7u 2 \u0111u\u00f4i l\u00e0 40 s\u1ed1 nh\u01b0ng c\u00f3 4 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 36 con.V\u00ed d\u1ee5 ch\u1ea1m 1,2 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1,2 v\u00e0 \u0111u\u00f4i 1,2, d\u00e0n n\u00e0y c\u00f3 4 s\u1ed1 tr\u00f9ng l\u00e0 11,22,12,21.<\/p>\n
T\u1ec9 l\u1ec7 ch\u01a1i : ch\u01a1i \u0111\u1ec1u ti\u1ec1n m\u1ed7i ng\u00e0y<\/p>\n
L\u00e3i n\u1ebfu tr\u00fang : 63 ngh\u00ecn<\/p>\n
2.3. D\u00e0n \u0111\u1eb7c bi\u1ec7t 51 s\u1ed1<\/span><\/h3>\nD\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 3 ch\u1ea1m g\u1ed3m 3 \u0111\u1ea7u v\u00e0 3 \u0111u\u00f4i l\u00e0 60 s\u1ed1 nh\u01b0ng c\u00f3 9 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 51 s\u1ed1.V\u00ed d\u1ee5 ch\u1ea1m 1,2,3 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1,2,3 v\u00e0 \u0111u\u00f4i 1,2,3, d\u00e0n n\u00e0y c\u00f3 9 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n l\u00e0 11,22,33,12,21,13,31,23,32.<\/p>\n
\n\n<\/div>\n<\/div>\n<\/div>\n2.4. D\u00e0n \u0111\u1eb7c bi\u1ec7t 64 s\u1ed1<\/span><\/h3>\nD\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 4 ch\u1ea1m g\u1ed3m 4 \u0111\u1ea7u v\u00e0 4 \u0111u\u00f4i l\u00e0 80 s\u1ed1 nh\u01b0ng c\u00f3 16 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 64 s\u1ed1.V\u00ed d\u1ee5 ch\u1ea1m 1,2,3,4 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1,2,3,4 v\u00e0 \u0111u\u00f4i 1,2,3,4,d\u00e0n n\u00e0y c\u00f3 16 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n l\u00e0 11,22,33,44,12,21,13,31,14,41,23,32,24,42,34,43.<\/p>\n
T\u1ec9 l\u1ec7 ch\u01a1i : ch\u01a1i \u0111\u1ec1u ti\u1ec1n m\u1ed7i ng\u00e0y<\/p>\n
L\u00e3i n\u1ebfu tr\u00fang : 35 ngh\u00ecn<\/p>\n
<\/p>\n
3. D\u00e0n \u0111\u1eb7c bi\u1ec7t nu\u00f4i 2 ng\u00e0y<\/span><\/h2>\nV\u1edbi ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u00fang ta c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng c\u00e1c d\u00e0n 36 s\u1ed1, 51 s\u1ed1.<\/p>\n
+ V\u1edbi d\u00e0n 36 s\u1ed1 ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i theo t\u1ec9 l\u1ec7 1:2.V\u00ed d\u1ee5 :<\/p>\n
Ng\u00e0y 1 m\u1ed7i con 1 ngh\u00ecn, ng\u00e0y 2 m\u1ed7i con 2 ngh\u00ecn.T\u1ed5ng v\u1ed1n l\u00e0 36 + 72 = 108 ngh\u00ecn.<\/p>\n
N\u1ebfu \u0103n ng\u00e0y 1 ch\u00fang ta l\u00e3i 63 ngh\u00ecn.<\/p>\n
N\u1ebfu \u0103n ng\u00e0y 2 ch\u00fang ta l\u00e3i 2*99 \u2013 108 = 90 ngh\u00ecn.<\/p>\n
+ V\u1edbi d\u00e0n 51 s\u1ed1 ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i theo t\u1ec9 l\u1ec7 1:3.V\u00ed d\u1ee5 :<\/p>\n
Ng\u00e0y 1 m\u1ed7i con 1 ngh\u00ecn, ng\u00e0y 2 m\u1ed7i con 3 ngh\u00ecn.T\u1ed5ng v\u1ed1n l\u00e0 51 + 153 = 204 ngh\u00ecn<\/p>\n
N\u1ebfu \u0103n ng\u00e0y 1 ch\u00fang ta l\u00e3i 48 ngh\u00ecn.<\/p>\n
N\u1ebfu \u0103n ng\u00e0y 2 ch\u00fang ta l\u00e3i 3*99 \u2013 204 = 93 ngh\u00ecn.<\/p>\n
4. D\u00e0n \u0111\u1eb7c bi\u1ec7t nu\u00f4i 3 ng\u00e0y<\/span><\/h2>\nV\u1edbi ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u00fang ta c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng c\u00e1c d\u00e0n 19 s\u1ed1, 36 s\u1ed1 \u0111\u1ec3 v\u1ed1n c\u00f3 th\u1ec3 \u00edt \u0111i v\u00e0 v\u1eabn \u0111\u1ea3m b\u1ea3o c\u00f3 l\u00e3i.<\/p>\n
+ V\u1edbi d\u00e0n 19 s\u1ed1 ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i theo t\u1ec9 l\u1ec7 1:2:3.V\u00ed d\u1ee5 :<\/p>\n
Ng\u00e0y 1 m\u1ed7i con 1 ngh\u00ecn, ng\u00e0y 2 m\u1ed7i con 2 ngh\u00ecn, ng\u00e0y 3 m\u1ed7i con 3 ngh\u00ecn.T\u1ed5ng v\u1ed1n : 19 + 19*2 + 19*3 = 114 .<\/p>\n
N\u1ebfu \u0103n ng\u00e0y 1 ch\u00fang ta l\u00e3i 99 \u2013 19 = 80 ngh\u00ecn.<\/p>\n
N\u1ebfu \u0103n ng\u00e0y 2 ch\u00fang ta l\u00e3i 99*2 \u2013 19 \u2013 19*2 = 141 ngh\u00ecn.<\/p>\n
N\u1ebfu \u0103n ng\u00e0y 3 ch\u00fang ta l\u00e3i 99*3 \u2013 19 \u2013 19*2 \u2013 19*3 = 183 ngh\u00ecn.<\/p>\n
+ V\u1edbi d\u00e0n 36 s\u1ed1 ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i theo t\u1ec9 l\u1ec7 1:3:10. V\u00ed d\u1ee5 :<\/p>\n
Ng\u00e0y 1 m\u1ed7i con 1 ngh\u00ecn, ng\u00e0y 2 m\u1ed7i con 3 ngh\u00ecn, ng\u00e0y 3 m\u1ed7i con 10 ngh\u00ecn.<\/p>\n
T\u1ed5ng v\u1ed1n : 36 + 36*3 + 36*10 = 504 ngh\u00ecn.<\/p>\n
N\u1ebfu \u0103n ng\u00e0y 1 ch\u00fang ta l\u00e3i : 99 \u2013 36 = 63 ngh\u00ecn.<\/p>\n
N\u1ebfu \u0103n ng\u00e0y 2 ch\u00fang ta l\u00e3i : 99*3 \u2013 36 -36*3 = 153 ngh\u00ecn.<\/p>\n
N\u1ebfu \u0103n ng\u00e0y 3 ch\u00fang ta l\u00e3i : 99*10 \u2013 504 = 486 ngh\u00ecn.<\/p>\n
Tr\u00ean \u0111\u00e2y \u0111\u00e3 gi\u1edbi thi\u1ec7u \u0111\u1ebfn c\u00e1c b\u1ea1n m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i d\u00e0n \u0111\u1eb7c bi\u1ec7t \u0111\u1ec3 kh\u1ea3 n\u0103ng c\u00f3 l\u00e3i cao khi ch\u01a1i<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n
soi c\u1ea7u mi\u1ec1n b\u1eafc vip<\/span><\/strong>\u200b<\/h2>\n
<\/p>\n<\/div>\n
<\/p>\n
B\u00e0i vi\u1ebft h\u00f4m nay xin g\u1eedi \u0111\u1ebfn c\u00e1c b\u1ea1n m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh d\u00e0n \u0111\u1eb7c bi\u1ec7t<\/strong><\/span> \u2013 d\u00e0n \u0111\u1ec1 x\u1ed5 s\u1ed1 3 mi\u1ec1n \u0111\u1ec3 c\u00f3 l\u00e3i v\u00e0 gi\u1ea3m thi\u1ec3u x\u00e1c su\u1ea5t tr\u01b0\u1ee3t nh\u1ea5t.<\/p>\n M\u1ee5c L\u1ee5c<\/p>\n D\u00e0n \u0111\u1eb7c bi\u1ec7t ngh\u0129a l\u00e0 ch\u01a1i nhi\u1ec1u s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t t\u1ea1o th\u00e0nh d\u00e0n nh\u01b0 : d\u00e0n \u0111\u1eb7c bi\u1ec7t 19 s\u1ed1, 36 s\u1ed1, 51 s\u1ed1, 64 s\u1ed1.<\/p>\n \u0110\u1ec3 ch\u01a1i \u0111\u01b0\u1ee3c theo c\u00e1c ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u00f3 l\u00e3i th\u00ec y\u1ebfu t\u1ed1 t\u1ec9 l\u1ec7 \u0103n r\u1ea5t quan tr\u1ecdng.B\u00ecnh th\u01b0\u1eddng ch\u00fang ta ghi b\u00ean ngo\u00e0i s\u1ebd \u0103n t\u1ec9 l\u1ec7 1 \u0103n 70, n\u01a1i n\u00e0o cao th\u00ec 1 \u0103n 80 ho\u1eb7c h\u01a1n 80 t\u00ed.<\/p>\n Ngh\u0129a l\u00e0 ch\u00fang ta gi 1 ngh\u00ecn \u0111\u1ec1 n\u1ebfu tr\u00fang \u0111\u01b0\u1ee3c 99 ngh\u00ecn, 1 \u0111i\u1ec3m l\u00f4 = 27 ngh\u00ecn n\u1ebfu tr\u00fang \u0111\u01b0\u1ee3c 99 ngh\u00ecn.<\/p>\n Sau \u0111\u00e2y, s\u1ebd chia s\u1ebb m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i d\u00e0n \u0111\u1ec1 \u0111\u1ec3 kh\u1ea3 n\u0103ng c\u00f3 l\u00e3i cao h\u01a1n.<\/p>\n V\u1edbi ph\u01b0\u01a1ng ph\u00e1p d\u00e0n \u0111\u1eb7c bi\u1ec7t ch\u01a1i trong ng\u00e0y n\u00e0y ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i c\u00e1c d\u00e0n 36 s\u1ed1, 51 s\u1ed1 ho\u1eb7c 64 s\u1ed1.<\/p>\n D\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 1 ch\u1ea1m ( 1 \u0111\u1ea7u v\u00e0 1 \u0111u\u00f4i ), 1 \u0111\u1ea7u 1 \u0111u\u00f4i l\u00e0 20 s\u1ed1 nh\u01b0ng c\u00f3 1 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 19 con.V\u00ed d\u1ee5 ch\u1ea1m 1 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1 v\u00e0 \u0111u\u00f4i 1 d\u00e0n n\u00e0y c\u00f3 1 s\u1ed1 tr\u00f9ng l\u00e0 11.<\/p>\n T\u1ec9 l\u1ec7 ch\u01a1i : ch\u01a1i \u0111\u1ec1u ti\u1ec1n m\u1ed7i ng\u00e0y<\/p>\n L\u00e3i n\u1ebfu tr\u00fang : 63 ngh\u00ecn<\/p>\n D\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 2 ch\u1ea1m ( 2 \u0111\u1ea7u v\u00e0 2 \u0111u\u00f4i ), 2 \u0111\u1ea7u 2 \u0111u\u00f4i l\u00e0 40 s\u1ed1 nh\u01b0ng c\u00f3 4 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 36 con.V\u00ed d\u1ee5 ch\u1ea1m 1,2 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1,2 v\u00e0 \u0111u\u00f4i 1,2, d\u00e0n n\u00e0y c\u00f3 4 s\u1ed1 tr\u00f9ng l\u00e0 11,22,12,21.<\/p>\n T\u1ec9 l\u1ec7 ch\u01a1i : ch\u01a1i \u0111\u1ec1u ti\u1ec1n m\u1ed7i ng\u00e0y<\/p>\n L\u00e3i n\u1ebfu tr\u00fang : 63 ngh\u00ecn<\/p>\n D\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 3 ch\u1ea1m g\u1ed3m 3 \u0111\u1ea7u v\u00e0 3 \u0111u\u00f4i l\u00e0 60 s\u1ed1 nh\u01b0ng c\u00f3 9 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 51 s\u1ed1.V\u00ed d\u1ee5 ch\u1ea1m 1,2,3 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1,2,3 v\u00e0 \u0111u\u00f4i 1,2,3, d\u00e0n n\u00e0y c\u00f3 9 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n l\u00e0 11,22,33,12,21,13,31,23,32.<\/p>\n D\u00e0n n\u00e0y \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh b\u1edfi 4 ch\u1ea1m g\u1ed3m 4 \u0111\u1ea7u v\u00e0 4 \u0111u\u00f4i l\u00e0 80 s\u1ed1 nh\u01b0ng c\u00f3 16 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n n\u00ean ch\u00fang ta lo\u1ea1i v\u00e0 ch\u1ec9 c\u00f2n 64 s\u1ed1.V\u00ed d\u1ee5 ch\u1ea1m 1,2,3,4 l\u00e0 bao g\u1ed3m \u0111\u1ea7u 1,2,3,4 v\u00e0 \u0111u\u00f4i 1,2,3,4,d\u00e0n n\u00e0y c\u00f3 16 s\u1ed1 l\u1eb7p l\u1ea1i 2 l\u1ea7n l\u00e0 11,22,33,44,12,21,13,31,14,41,23,32,24,42,34,43.<\/p>\n T\u1ec9 l\u1ec7 ch\u01a1i : ch\u01a1i \u0111\u1ec1u ti\u1ec1n m\u1ed7i ng\u00e0y<\/p>\n L\u00e3i n\u1ebfu tr\u00fang : 35 ngh\u00ecn<\/p>\n <\/p>\n V\u1edbi ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u00fang ta c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng c\u00e1c d\u00e0n 36 s\u1ed1, 51 s\u1ed1.<\/p>\n + V\u1edbi d\u00e0n 36 s\u1ed1 ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i theo t\u1ec9 l\u1ec7 1:2.V\u00ed d\u1ee5 :<\/p>\n Ng\u00e0y 1 m\u1ed7i con 1 ngh\u00ecn, ng\u00e0y 2 m\u1ed7i con 2 ngh\u00ecn.T\u1ed5ng v\u1ed1n l\u00e0 36 + 72 = 108 ngh\u00ecn.<\/p>\n N\u1ebfu \u0103n ng\u00e0y 1 ch\u00fang ta l\u00e3i 63 ngh\u00ecn.<\/p>\n N\u1ebfu \u0103n ng\u00e0y 2 ch\u00fang ta l\u00e3i 2*99 \u2013 108 = 90 ngh\u00ecn.<\/p>\n + V\u1edbi d\u00e0n 51 s\u1ed1 ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i theo t\u1ec9 l\u1ec7 1:3.V\u00ed d\u1ee5 :<\/p>\n Ng\u00e0y 1 m\u1ed7i con 1 ngh\u00ecn, ng\u00e0y 2 m\u1ed7i con 3 ngh\u00ecn.T\u1ed5ng v\u1ed1n l\u00e0 51 + 153 = 204 ngh\u00ecn<\/p>\n N\u1ebfu \u0103n ng\u00e0y 1 ch\u00fang ta l\u00e3i 48 ngh\u00ecn.<\/p>\n N\u1ebfu \u0103n ng\u00e0y 2 ch\u00fang ta l\u00e3i 3*99 \u2013 204 = 93 ngh\u00ecn.<\/p>\n V\u1edbi ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ch\u00fang ta c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng c\u00e1c d\u00e0n 19 s\u1ed1, 36 s\u1ed1 \u0111\u1ec3 v\u1ed1n c\u00f3 th\u1ec3 \u00edt \u0111i v\u00e0 v\u1eabn \u0111\u1ea3m b\u1ea3o c\u00f3 l\u00e3i.<\/p>\n + V\u1edbi d\u00e0n 19 s\u1ed1 ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i theo t\u1ec9 l\u1ec7 1:2:3.V\u00ed d\u1ee5 :<\/p>\n Ng\u00e0y 1 m\u1ed7i con 1 ngh\u00ecn, ng\u00e0y 2 m\u1ed7i con 2 ngh\u00ecn, ng\u00e0y 3 m\u1ed7i con 3 ngh\u00ecn.T\u1ed5ng v\u1ed1n : 19 + 19*2 + 19*3 = 114 .<\/p>\n N\u1ebfu \u0103n ng\u00e0y 1 ch\u00fang ta l\u00e3i 99 \u2013 19 = 80 ngh\u00ecn.<\/p>\n N\u1ebfu \u0103n ng\u00e0y 2 ch\u00fang ta l\u00e3i 99*2 \u2013 19 \u2013 19*2 = 141 ngh\u00ecn.<\/p>\n N\u1ebfu \u0103n ng\u00e0y 3 ch\u00fang ta l\u00e3i 99*3 \u2013 19 \u2013 19*2 \u2013 19*3 = 183 ngh\u00ecn.<\/p>\n + V\u1edbi d\u00e0n 36 s\u1ed1 ch\u00fang ta c\u00f3 th\u1ec3 ch\u01a1i theo t\u1ec9 l\u1ec7 1:3:10. V\u00ed d\u1ee5 :<\/p>\n Ng\u00e0y 1 m\u1ed7i con 1 ngh\u00ecn, ng\u00e0y 2 m\u1ed7i con 3 ngh\u00ecn, ng\u00e0y 3 m\u1ed7i con 10 ngh\u00ecn.<\/p>\n T\u1ed5ng v\u1ed1n : 36 + 36*3 + 36*10 = 504 ngh\u00ecn.<\/p>\n N\u1ebfu \u0103n ng\u00e0y 1 ch\u00fang ta l\u00e3i : 99 \u2013 36 = 63 ngh\u00ecn.<\/p>\n N\u1ebfu \u0103n ng\u00e0y 2 ch\u00fang ta l\u00e3i : 99*3 \u2013 36 -36*3 = 153 ngh\u00ecn.<\/p>\n N\u1ebfu \u0103n ng\u00e0y 3 ch\u00fang ta l\u00e3i : 99*10 \u2013 504 = 486 ngh\u00ecn.<\/p>\n Tr\u00ean \u0111\u00e2y \u0111\u00e3 gi\u1edbi thi\u1ec7u \u0111\u1ebfn c\u00e1c b\u1ea1n m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i d\u00e0n \u0111\u1eb7c bi\u1ec7t \u0111\u1ec3 kh\u1ea3 n\u0103ng c\u00f3 l\u00e3i cao khi ch\u01a1i<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n
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1.Ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i d\u00e0n \u0111\u1eb7c bi\u1ec7t<\/span><\/h2>\n
2. D\u00e0n \u0111\u1eb7c bi\u1ec7t ch\u01a1i trong ng\u00e0y<\/span><\/h2>\n
2.1. D\u00e0n \u0111\u1eb7c bi\u1ec7t 19 s\u1ed1<\/span><\/h3>\n
2.2. D\u00e0n \u0111\u1eb7c bi\u1ec7t 36 s\u1ed1<\/span><\/h3>\n
2.3. D\u00e0n \u0111\u1eb7c bi\u1ec7t 51 s\u1ed1<\/span><\/h3>\n
2.4. D\u00e0n \u0111\u1eb7c bi\u1ec7t 64 s\u1ed1<\/span><\/h3>\n
3. D\u00e0n \u0111\u1eb7c bi\u1ec7t nu\u00f4i 2 ng\u00e0y<\/span><\/h2>\n
4. D\u00e0n \u0111\u1eb7c bi\u1ec7t nu\u00f4i 3 ng\u00e0y<\/span><\/h2>\n
soi c\u1ea7u mi\u1ec1n b\u1eafc vip<\/span><\/strong>\u200b<\/h2>\n